8b^2+56b=-

Solution for 8b^2+56b=- equation:

8b^2+56b=-

We move all terms to the left:

8b^2+56b-(-)=0

We add all the numbers together, and all the variables

8b^2+56b-0=0

We add all the numbers together, and all the variables

8b^2+56b=0

a = 8; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·8·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*8}=\frac{-112}{16}
=-7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*8}=\frac{0}{16}
=0
$